[2x(3x-4)]-[x(6x-2)]=32

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Solution for [2x(3x-4)]-[x(6x-2)]=32 equation: 


Simplifying
[2x(3x + -4)] + -1[x(6x + -2)] = 32

Reorder the terms:
[2x(-4 + 3x)] + -1[x(6x + -2)] = 32
[(-4 * 2x + 3x * 2x)] + -1[x(6x + -2)] = 32
[(-8x + 6x2)] + -1[x(6x + -2)] = 32
[-8x + 6x2] + -1[x(6x + -2)] = 32

Remove brackets around [-8x + 6x2]
-8x + 6x2 + -1[x(6x + -2)] = 32

Reorder the terms:
-8x + 6x2 + -1[x(-2 + 6x)] = 32
-8x + 6x2 + -1[(-2 * x + 6x * x)] = 32
-8x + 6x2 + -1[(-2x + 6x2)] = 32
-8x + 6x2 + [-2x * -1 + 6x2 * -1] = 32
-8x + 6x2 + [2x + -6x2] = 32

Reorder the terms:
-8x + 2x + 6x2 + -6x2 = 32

Combine like terms: -8x + 2x = -6x
-6x + 6x2 + -6x2 = 32

Combine like terms: 6x2 + -6x2 = 0
-6x + 0 = 32
-6x = 32

Solving
-6x = 32

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-6'.
x = -5.333333333

Simplifying
x = -5.333333333

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